x^2+20x-3600=0

Solution for x^2+20x-3600=0 equation:

x^2+20x-3600=0

a = 1; b = 20; c = -3600;
Δ = b2-4ac
Δ = 202-4·1·(-3600)
Δ = 14800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{14800}=\sqrt{400*37}=\sqrt{400}*\sqrt{37}=20\sqrt{37}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20\sqrt{37}}{2*1}=\frac{-20-20\sqrt{37}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20\sqrt{37}}{2*1}=\frac{-20+20\sqrt{37}}{2}
$